Answer:
The new mean would be given by:
[tex] \bar X_f = \frac{\sum_{i=1}^n X +X_1}{28+25}[/tex]
And replacing we got:
[tex] \bar X_f = \frac{2340.8+ 1720}{28+25}= 76.6[/tex]
Step-by-step explanation:
We know that the original mean from the 28 students is given by:
[tex] \bar X= \frac{\sum_{i=1}^{28} X_i}{28}= 83.6[/tex]
The sum of the values is:
[tex] \sum_{i=1}^{28} X_i = 28*83.6 =2340.8[/tex]
And now we know that the new mean is 68.8 with the 25 new people so then the new mean would be given by:
[tex] \bar X_1 = \frac{\sum_{i=1}^{25} X_i}{25} = 68.8[/tex]
The sum of the values is:
[tex] \sum_{i=1}^{25} X_i = 25*68.8 =1720[/tex]
The new mean would be given by:
[tex] \bar X_f = \frac{\sum_{i=1}^n X +X_1}{28+25}[/tex]
And replacing we got:
[tex] \bar X_f = \frac{2340.8+ 1720}{28+25}= 76.6[/tex]