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19-06-2020
Mathematics

contestada

64x^2 + 128x − 4y^2 + 32y + 256 = 0

Respuesta :

Victoriat4989 Victoriat4989

19-06-2020

Answer:

x=−1+

4

√

(y−12)(y+4)

,−1−

4

√

(y−12)(y+4)

Step-by-step explanation:

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