Answer:
The speed of light moving along the shoreline when it is 1 km from P is 2.1064 km
Step-by-step explanation:
We are given that a point 1 km from point P on the shoreline would form a a right triangle with the lighthouse, point P, and the point 1 km from point P.
The distance from that point to the lighthouse would be the hypotenuse.
That would also be the radius of the circle the beam of light is making at that point.
To find the hypotenuse
[tex]Hypotenuse^2 = Perpendicular^2 +base^2 \\r^2 = 1^2 +2^2\\r=\sqrt{1^2+2^2}\\r=2.236[/tex]
Circumference =[tex]2 \pi r = 2 \times 3.14 \times 2.236=14.05 km[/tex]
The beam of light is making at point 14.05 km away
One revolution: [tex]\frac{60}{9}= 6.67[/tex] sec per revolution
Speed = [tex]\frac{14.05}{6.67}=2.1064[/tex]
Hence The speed of light moving along the shoreline when it is 1 km from P is 2.1064 km