a] plot a graph of extension against load using the given data
b] find the extension when the load is 2.5n
c] mark the elastic limit (E) or the above spring
d] from the graph write down how extension and load are connected

a plot a graph of extension against load using the given data b find the extension when the load is 25n c mark the elastic limit E or the above spring d from th class=

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Answer:

See the explanation

Explanation:

PART A

Load is plotted at x-axis, Extension is plotted at y-axis

(The graph is attached below)

PART B

As we can see that within the elastic limit

for x = 1 , y = 5

for x =2 , y = 10

for x = 3, y = 15

We can deduce the function as

y = 5x

So for x = 2.5N

y = 5(2.5)

y = 12.5 mm

(This can also be found by using graph)

PART C

Elastic limit is the point beyond which the deformation doesn't follow the function and acts abnormally.

We can see in the graph that after x = 5 N , the graph doesn't follow the function y = 5x , so the elastic limit is at Load 5 N

PART D

Extension and load are linearly connected by the function y = 5x where y is the deformation and x is the load. This functions holds up till elastic limit, after which it acts abnormally.

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