the table show the age in years of employees in a company
![the table show the age in years of employees in a company class=](https://us-static.z-dn.net/files/ddb/e56d5f53b0c4db44fbb94e13c5c3a74e.png)
Answer:
A. 24 ≤ a < 26.
B. 22.5
Step-by-step explanation:
A. Determination of the modal class interval.
Mode is the class with the highest frequency.
From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:
24 ≤ a < 26.
B. To obtain the mean, we must determine the class mark. This is illustrated below:
Class >>>>> class mark >>> frequency
18 – 19 >>>> 18.5 >>>>>>>>> 3
20 – 21 >>> 20.5 >>>>>>>> 2
22 – 23 >>> 22.5 >>>>>>>> 7
24 – 25 >>> 24.5 >>>>>>>> 8
26 >>>>>>>> 26 >>>>>>>>> 0
The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:
Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)
Mean = (55.5 + 41 + 157.5 + 196 + 0)/20
Mean = 450/20
Mean = 22.5
Therefore, the mean age is 22.5
Answer:
23
Step-by-step explanation:
To work out the mean estimate you need to devide
(sum of midpoint x frequency) by (sum of frequency).
Sum of Frequency:
3+2+7+8+0
= 20
sum of (MPF):
Frequency x Midpoint
3x19=57
2x21=42
7x23=161
8x25=200
0x27=0
57+42+161+200+0
= 460
Mean Estimate:
460/20
=23