If the object represented by the FBD below has a mass of 2.0 kg, what is the
acceleration of the object?
![If the object represented by the FBD below has a mass of 20 kg what is the acceleration of the object class=](https://us-static.z-dn.net/files/d45/2bf4b052f7490503a269d3bedecc7d8e.png)
Answer: B
Explanation:
Let us first resolve the forces.
Horizontal, the vectorial resolution is equal to zero. Since the positive direction and negative direction vector are of same magnitude. Therefore, summation of horizontal forces Fh = 0
Vertical resolution, the sum of forces will be Fv = 30 - 35 = - 5 N
Resultant force F = sqrt( Fv^2 + Fh^2)
Substitutes Fv and Fh. We get
R = sqrt ( 25) = 5N
We are given that the mass M = 2kg
From Newton second law,
F = Ma
Where a = acceleration
Substitute F and M and make a the subject of formula
5 = 2a
a = 5/2 = 2.5 m/s^2
Therefore, acceleration a of the object is 2.5 m/s^2 down.