Question

64y^2+4y-3
guys plz factorise this for me​

Answer 1

Step-by-step explanation:

64y^2+(16-12)y-3

=64y^2+16y-12y-3

=16y(4y+1)-3(4y+1)

=(16y-3) (4y+1)

Answer 2

Answer: $(16y-3)(4y+1)$

Step-by-step explanation:

$64y^{2}+4y-3$

$64y^{2}+16y-12y-3$

$(64y^{2}+16y)+(-12y-3)$

$16y(4y+1)-3(4y+1)$

$(16y-3)(4y+1)$