Step-by-step explanation:
Given
w(x) = ax²+ bx +c
a=3
Soln.
w(3) = w(15) = 0
w(x) = ax² + bx + c
w(3) = a(3)² + b(3) + c ( Replace x by 3)
= 9a + 3b +c
a=3( given)
w(3) = 9(3) + 3b + c
= 27 +3b + c =0. .....(1)
w(15) = a(15)² + b(15) + c ( Replacing x by 15)
= 225a + 15b + c
a= 3(given)
w(15) = 225(3)+ 15b + c
= 675 + 15b + c = 0. .....(2)
Now solve the 2 equations by subtracting
15b + c + 675 = 0
(-) 3b + c + 27 = 0
________________
12b + 648 = 0
12b = -648
b= -648/12 = -54
Now absolute value of b = |b| = |-54| = 54.
Hope this answer helps you
