Question

a²+2ab+b²-ac-bc=?
Please help me​

Answer 1

Answer:

(a+b)(a+b-c)

Step-by-step explanation:

Formula:

(a+b)² = a² + b² + 2ab

Therefore,

a²+b²+2ab -ac-bc

= (a+b)² -ac-bc

Now take -c common in ac and bc

(a+b)² -c(a+b)

now take (a+b) common in both terms

(a+b)(a+b-c)

.

Hope it helps