Answer:
Option (2).
Step-by-step explanation:
Let f(x) and g(x) are the two functions with domain A and B.
Then (fg)(x) will be the function with domain A∩B
(fg)(x) = f(x)g(x) Domain : A∩B
In this question two functions are,
c(x) = [tex]\frac{5}{(x-2)}[/tex] and d(x) = (x + 3)
Domain : (x - 2) > 0 ⇒ x > 2
and (x - 2) < 0 ⇒ x < 2
Or domain of (cd)(x) will be C = (-∞, 2)∪(2, ∞).
Similarly, d(x) = x + 3
Domain : All real numbers
: D = (-∞, ∞)
(cd)(x) = c(x)d(x)
= [tex]\frac{5}{(x-2)}\times (x+3)[/tex]
Domain of (cd)(x) will be,
Domain : C∩D = (-∞, 2)∪(2, ∞) ∩ (-∞, ∞)
: (-∞, 2) ∩ (2, ∞)
Therefore, domain of (cd)(x) will be all real values except 2.
Option (2) will be the answer.
