Respuesta :

Answer:

x = 10,-4

Step-by-step explanation:

(x-3)^2 -49 = (x-3-7)(x-3+7)

= (x-10)(x+4)

The zeros of f(x) are 10 ,-4

What is Expansion?

  • An expansion of a product of sums expresses it as a sum of products by using the fact that multiplication distributes over addition

How to Solve this Problem?

This problem can be solved by following steps

  • The given equation is equal to zero
  • Expand (x-3)^2
  • Split the middle term
  • Take the common factors
  • And find out the zeros of the equation

[tex]f(x)=0\\(x-3)^{2}-49=0\\ x^{2} -6x-40=0\\x^{2} -10x+4x-40=0\\x(x-10)+4(x-10)\\(x-10)(x+4)\\x = 10 , -4[/tex]

Hence the zeroes are 10 and -4

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