Question

Prove that: (1+cot^2x)tan^2x = sec^2x

Answer 1

Answer:

Step-by-step explanation:

$1+cot^2x = csc^2x= \frac{1}{sin^2x}$

it becomes

$\frac{1}{sin^2x}*\frac{sin^2x}{cos^2x}=\frac{1}{cos^2x}=sec^2x$

Done