Question

PLEASE HELP!! if sec x=5/3 what is the value of b? NL=20 LM=3b angle of L is x degrees.


a. b=4

b. b=5

c. b=6

d. b=7

Answer 1

Answer:

a. b=4

Step-by-step explanation:

$\sec \theta =\dfrac{1}{\cos \theta} = \dfrac{Hypotenuse}{Adjacent}$

From the attached triangle drawn below:

NL=20,  LM=3b, $\angle L=x^\circ$

$\sec x =\dfrac{20}{3b}$

Since we are told that:

$\sec x =\dfrac{5}{3}\\ Then:\\\dfrac{20}{3b} =\dfrac{5}{3}\\ Cross multiply\\5 \times 3b =20 \times 3\\15b=60\\ Divide both sides by 15\\15b \div 15 =60 \div 15\\b=4$

The correct option is A.

Answer 2

Answer:

B= 4

Step-by-step explanation:

I got it right on the test