dyl22602 dyl22602

19-06-2020
Mathematics

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Apple weights in an orchard are normally distributed. From a sample farmer Fred determines the mean weight of a box of apples to be 270 oz. with a standard deviation of 10 oz. He wonders what percent of the apple boxes he has grouped for sale will have a weight less than 255 oz.

Apple weights in an orchard are normally distributed From a sample farmer Fred determines the mean weight of a box of apples to be 270 oz with a standard deviat class=

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Minecraftgirl6294 Minecraftgirl6294

19-06-2020

Answer:

2.07 is the answer as of e.2020

Step-by-step explanation:

Mean = 270 Standard deviation = 10 x = 255 Formula for z-score, z = (x - mean)/SD z = (255 - 270) / 10 => z = -15 / 10 => z = -1.5 So by referring to z-table, -1.5 correlates to 0.0668 that implies to 0.07 So 7% of the boxes of Apples weight less than 255oz. The percentage of boxes is in the range of 255 oz and 270 oz, Now calculating the requiring percentage 50% - 7% = 43%

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hansikas1 hansikas1

19-06-2020

Answer:

2.07 is the answer as of e.2020

Step-by-step explanation:

Answer Link

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