Respuesta :
Answer:
The critical values of r are -0.708 and 0.708.
Step-by-step explanation:
A statistical test is being performed to determine whether there is any linear correlation between two variables.
The hypothesis can be defined as follows:
H₀: There is no linear correlation between two variables, i.e. ρ = 0.
Hₐ: There is a significant linear correlation between two variables, i.e. ρ ≠ 0.
The test statistic is given as follows:
[tex]t = \frac{r\sqrt{n-2}}{\sqrt{1-r^{2}}}[/tex]
The degrees of freedom of the test is:
[tex]\text{df}=n-2=12-2=10[/tex]
The significance level of the test is, α = 0.01.
The critical values of r are:
[tex]r_{\alpha/2, (n-2)}=r_{0.01/2, (12-2)}=r_{0.005, 10}=\pm0.708[/tex]
*Use the r critical value table.
Thus, the critical values of r are -0.708 and 0.708.
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From the 'r' table, the values of 'r' are -0.708 and 0.708.and this can be determined by using the hypothesis test.
Given :
- Suppose you will perform a test to determine whether there is sufficient evidence to support the claim of a linear correlation between two variables.
- Number of pairs of data n and the significance level a is n = 12, a = 0.01.
The hypothesis test is performed in this problem. The null and alternate hypothesis is:
[tex]\rm H_0 : p=0\\[/tex]
[tex]\rm H_1:p\neq 0[/tex]
The t-statistics is given by:
[tex]\rm t =\dfrac{r\sqrt{n-2} }{\sqrt{1-r^2} }[/tex]
Degree of freedom is given by:
df = n - 2 = 12 - 2 = 10
The significance level for this test is [tex]\alpha = 0.01[/tex]
Now, the critical value r is given by:
[tex]\rm r_{\alpha /2,(n-2)}=r_{0.01/2,(12-2)}=r_{0.005,10} = \pm0.708[/tex]
So, from the 'r' table, the values of 'r' are -0.708 and 0.708.
For more information, refer to the link given below:
https://brainly.com/question/2817633