Question

consider the quadratic equation y^2-y=6. what is the error with the solution below?

Answer 1

Answer:

y=-2 or y=3

Step-by-step explanation:

Y^2-y-6=0

y^2-3y+2y-6=0

y(y-3)+2(y-3)=0

(y+2)(y-3)=0

y=-2 or y=3

hope it helps