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A hydrogen line in a star's spectrum
has a frequency of 6.17x1014 Hz
when stationary. In Rigel's spectrum,
it is shifted downward by 4.26x1010
Hz. What is Rigel's velocity relative
to us?

Respuesta :

Answer:

Riegel's velocity relative to us is: [tex]v_{r} = 2.07 * 10^4 m/s[/tex]

Explanation:

Frequency of Riegel's spectrum, [tex]f_{r} = f - f'[/tex]

[tex]f' = f - f_{r} = 4.26 * 10^{10} Hz[/tex]

From the relativistic doppler effect, the wavelength of Riegel's spectrum is:

[tex]\lambda = \lambda_{r} (1 - \frac{v_{r} }{c} )\\\frac{c}{f} = \frac{c}{f_r} (1 - \frac{v_{r} }{c} )\\v_{r} = (\frac{f - f_r}{f} )c\\Since, f' = f - f_r\\v_{r} = (\frac{f'}{f} )c\\v_{r} = (\frac{4.26 * 10^{10}}{6.17 * 10^{14}} ) * (3 * 10^8)\\v_{r} = 2.07 * 10^4 m/s[/tex]

Answer:

The answer is 20713.13.

Explanation:

The previous answerer did everything correctly but left the answer in its unexpanded form. For Acellus, this is the correct answer.

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