Answer:
(i) [tex]80-x[/tex]
(ii) [tex]S(x) = 40 - 0.10x[/tex]
(iii) $36.5
Step-by-step explanation:
Given that:
1. Total Number of fruits = 80
2. Number of mangoes = x
3. Both mangoes and oranges are there in the basket.
Solution (i):
Only mangoes and oranges are there in the basket and the basket is full.
so, Number of mangoes + Number of oranges = Total number of fruits
x + Number of oranges = 80
Number of oranges = [tex]80 -x[/tex]
Solution (ii):
Given:
Cost of an orange = 50 cents = $0.50
Cost of a mango = 40 cents = $0.40
Cost for x mangoes = [tex]\$ 0.40x[/tex]
Cost for ([tex]80-x[/tex]) oranges = [tex]\$ 0.50 \times (80-x)[/tex]
[tex]\Rightarrow S(x) = 0.50 (80-x) + 0.40x\\\Rightarrow S(x) = 40 -0.50x + 0.40x\\\Rightarrow S(x) = 40 - 0.10x[/tex]
Solution (iii):
Put value of x = 35 in S(x)
[tex]S(35) = 40 - 0.10 (35)\\\Rightarrow S(35) = 40 - 0.35\\\Rightarrow S(35) =\$ 36.5[/tex]
Hence, answers are:
(i) [tex]80-x[/tex]
(ii) [tex]S(x) = 40 - 0.10x[/tex]
(iii) $36.5