Question

What is the correct equilibrium constant expression for the following reaction? 3A2 = 2B3 when the reaction started with the initial concentrations of A2 = 3 M and B3 = 2 M and continued until the equilibrium concentrations of A2 = 2.5 M and B3 = 2.5 M

Answer 1

Answer:

Kc = [B₃]²/[A₂]³  = 0.40

Explanation:

3A₂ ⇄ 2B₃  

Given at equilibrium =>  [A₂] =2.5 and [B₃] = 2.5

Kc = [B₃]²/[A₂]³ = (2.5)²/(2.5)³ = (2.5)⁻¹ = 0.40