*See attachment for the pyramid being referred to here
Answer:
166 square unit
Step-by-step explanation:
==>Given:
From the attachment, we are given the 2-dimensional diagram of the 3-dimensional diagram of the pyramid showing the dimensions of each faces as follows:
2 triangular faces=> base (b) = 2; height (h) = 13
2 triangular faces=> base (b) = 10; height (h) = 12
1 rectangular face=> length (l) = 10; width (w) = 2
==>Required:
Surface area of the pyramid = sum of area of all the faces
==>Solution:
Sum of surface area of all the faces = area of the 4 triangular faces + area of rectangular face
=>Area of the first 2 similar triangles with b = 2, h = 13 would be 2*(½bh)
= 2*(½*2*13)
= 2*(13)
= 26 square unit
==>area of the second set of 2 similar triangular faces with b = 10, h = 12 would be 2*(½bh)
= 2*(½*10*12)
= 2*(60)
= 120 square unit
==>Are of the rectangular face with l = 10, w = 2 would be l × w:
Area = 10 × 2 = 20 square unit
Total surface area of the pyramid = 26 + 120 + 20 = 166 square unit
Answer:
B.166
Step-by-step explanation:
Got it right on Edge 2020 :)
