Question

What is the following sum? 4 (RootIndex 5 StartRoot x squared y EndRoot) + 3 (RootIndex 5 StartRoot x squared y EndRoot) 7 (RootIndex 10 StartRoot x squared y EndRoot) 7 (RootIndex 10 StartRoot x Superscript 4 Baseline y squared EndRoot) 7 (RootIndex 5 StartRoot x squared y EndRoot) 7 (RootIndex 5 StartRoot x Superscript 4 Baseline y squared EndRoot)

Answer 1

Answer:

$7\sqrt[5]{x^2y}$

Step-by-step explanation:

Given

$4\sqrt[5]{x^2y} + 3\sqrt[5]{x^2y}$

Required

Calculate Sum

Questions like this are best answered by looking for common factor and factorizing the given expressions;

From the given expression $\sqrt[5]{x^2y}$ is common in both;

$4(\sqrt[5]{x^2y}) + 3(\sqrt[5]{x^2y})$

So, we start by factorizing the given expression; i.e. bring out the common terms... This gives

$(4 + 3)\sqrt[5]{x^2y}$

Solve the bracket

$(7)\sqrt[5]{x^2y}$

Open Bracket

$7 * \sqrt[5]{x^2y}$

$7\sqrt[5]{x^2y}$

Hence, $4\sqrt[5]{x^2y} + 3\sqrt[5]{x^2y}$ is equivalent to $7\sqrt[5]{x^2y}$

Answer 2

The sum of the expression; 4 (RootIndex 5 StartRoot x squared y EndRoot) + 3 (RootIndex 5 StartRoot x squared y EndRoot) is; 7 ⁵√x²y.

Sum of roots;

The given expression 4 (RootIndex 5 StartRoot x squared y EndRoot) + 3 (RootIndex 5 StartRoot x squared y EndRoot) can be written mathematically as;

$4 \sqrt[5]{ {x}^{2} y } + 3\sqrt[5]{ {x}^{2} y }$

By observation, we can conclude that ⁵√x²y is a common factor; so that we have;

• ⁵√x²y(4 +3)

Ultimately, the sum is; 7 ⁵√x²y.

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