Respuesta :

Answer:

[tex]x=\sqrt{y-2}[/tex]

Step-by-step explanation:

[tex]y=x^{2} +2[/tex]

[tex]y-2=x^{2}[/tex]

[tex]\sqrt{y-2} =x[/tex]

Answer:

[tex]x= y\sqrt{x} -2[/tex] That could be the answer if I did it right, I haven't done this since 8th grade so not sure. Hope it helps tho

Step-by-step explanation:

SO first thing I'd do is subtract two from both sides

[tex]y=x^2+2[/tex]

-2        -2

[tex]y-2=x^2[/tex]

Then to solve it, do the opposite of squaring X, so square root it

[tex]y-2=x^2[/tex]

[tex]\sqrt{x} \\[/tex]       [tex]\sqrt{x} \\[/tex]

[tex]x= y\sqrt{x} -2[/tex]

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