Respuesta :
Answer:
[tex]x=\sqrt{y-2}[/tex]
Step-by-step explanation:
[tex]y=x^{2} +2[/tex]
[tex]y-2=x^{2}[/tex]
[tex]\sqrt{y-2} =x[/tex]
Answer:
[tex]x= y\sqrt{x} -2[/tex] That could be the answer if I did it right, I haven't done this since 8th grade so not sure. Hope it helps tho
Step-by-step explanation:
SO first thing I'd do is subtract two from both sides
[tex]y=x^2+2[/tex]
-2 -2
[tex]y-2=x^2[/tex]
Then to solve it, do the opposite of squaring X, so square root it
[tex]y-2=x^2[/tex]
[tex]\sqrt{x} \\[/tex] [tex]\sqrt{x} \\[/tex]
[tex]x= y\sqrt{x} -2[/tex]