Answer:
Major product: 3-bromo-2,2,4-trimethylpentane
Minor product: 2-bromo-2,4,4-trimethylpentan
Explanation:
In this case, we will have an anti-markovnikov reaction. So, the Br (the nucleophile would be added in the least substituted carbon (in the double bond). On this molecule, the least substituted carbon of the double bond is the carbon in the left, therefore, the major product would be 3-bromo-2,2,4-trimethylpentane. With this in mind, the minor product would be the addition product in which the "Br" is added in the most substituted carbon of the double bond (carbon in the right) and we will have as a product 2-bromo-2,4,4-trimethylpentane. (See figure 1)
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