Answer:
value of 4 tan 45° +(2 sin 45°) (6 cos 45°) is 10.
Step-by-step explanation:
To solve this question we need to know value of
tan 45° = 1
sin 45° = [tex]1/\sqrt{2}[/tex]
cos 45° = [tex]1/\sqrt{2}[/tex]
we will be using above value sin the given expression as shown
[tex]4 tan 45 +(2 sin 45) (6 cos 45) = 4*1 + (2*1/\sqrt{2} )(6*1/\sqrt{2})\\ = 4 + (2/\sqrt{2}) (6/\sqrt{2})\\= 4 + (2*6)/(\sqrt{2}*\sqrt{2})\\= 4 + (12/2)\\= 4 + 6 = 10[/tex]
Thus, value of 4 tan 45° +(2 sin 45°) (6 cos 45°) is 10.
