Question

An aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 30mm in diameter and is 100mm long. If the modulus of elasticity for the aluminium is 85GN/m2, calculate the total contraction on the bar due to a compressive load of 180kN.

Answer 1

Answer:

Explanation:

l = 600mm = 0.6m

d = 40mm = 0.04m

hd = 30mm = 0.03m (diameter of the hole)

hl = 100mm = 0.1m (hole length)

modulus of elasticity for the aluminium = 85GN/m2

compressive load = 180kN