A DEF is a right triangle.
![A DEF is a right triangle class=](https://us-static.z-dn.net/files/de1/1a6e5113725841f47a8b3ebea692b4de.png)
Answer:
The statement is false because ΔDEF is not a right triangle.
Step-by-step explanation:
We can figure out if this triangle is a right triangle by using the Pythagorean Theorem. The Pythagorean Theorem is a² + b² = c².
a = 26
b = 27
c = 48
Now, let's plug these numbers into the formula.
(26)² + (27)² = (48)²
676 + 729 = 2304
1405 = 2304
1405 does not equal to 2304.
So, ΔDEF is not a right triangle.
The Pythagorean Theorem states that in a right triangle, [tex]a^{2} + b^{2} = c^{2}[/tex], where a and b are the legs and c is the hypotenuse.
Plugging in this formula, we can identify if DEF is a right triangle.
[tex]25^{2} +27^{2} = c^{2}[/tex]
The first step is to plug in our known values.
[tex]625 + 729 = c^{2}[/tex]
Next, we'll square both values available.
[tex]1354 = c^{2}[/tex]
From there, we'll add the values together.
[tex]36.7967.. = c[/tex]
Finally, we'll find the square root of our value to get c.
Since our answer is ~36, and the value we're given for the hypotenuse is 48, this is not a right triangle since the values aren't the same.
Therefore, the answer is False.
Hope this helped! :)