Question

What’s the correct answer for this question?

Answer 1

Answer:

$6$

Step-by-step explanation:

In the given figure, secants PA and PC are intersecting outside of the circle at point P.

PA = PB + AB = 7 + 5 = 12

PC = 14, PD =?

By the property of intersecting secants outside of a circle:

$PB \times PA = PD\times PC\\

\therefore 7\times 12 = PD \times 14\\

\therefore 84 =PD \times 14\\\\

\therefore PD = \frac{84}{14}\\\\

\therefore PD = 6\\\\

$

Answer 2

Answer: PD = 6

Step-by-step explanation:

PD = PB + AB = 12

When two secant lines intersect each other outside a circle, the products of their segments are equal. This is:

PB x PA = PD x PC

7 x 12 = PD x 14

PD = 7 x 12 / 14

PD = 6