What is the area of parallelogram ABCD?
O 13 square units
O 14 square units
O 15 square units
O 16 square units

What is the area of parallelogram ABCD O 13 square units O 14 square units O 15 square units O 16 square units class=

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Answer:

The area of ABCD is 13 square units.

Step-by-step explanation:

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The area of the shown rectangle is 13 square units.

What is the area of the parallelogram?

We have a rectangle, remember that the area of a rectangle of length L and width W is equal to:

area = W*L

Here we can define the length as the distance AB.

A = (3, 6) and B = (6, 5).

Then the distance between these points is:

[tex]L = \sqrt{(3 - 6)^2 + (6 - 5)^2} = \sqrt{10}[/tex]

And the width is the distance AD, then:

A = (3, 6) and D = (2, 2), so we have:

[tex]W = \sqrt{(3 - 2)^2 + (6 - 2)^2} = \sqrt{17}[/tex]

Then the area is:

area = √10*√17 = √(10*17) = √170 = 13 square units.

If you want to learn more about rectangles:

https://brainly.com/question/17297081

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