Answer:
0.5472 moles of H₂O are produced
0.1992 moles of C₈H₁₈ were left
Explanation:
The reaction of octane (C₈H₁₈) with oxygen (O₂) is:
C₈H₁₈ + 25/2 O₂ → 8CO₂ + 9H₂O
Where 1 mole of octane reacts with 25/2 moles of oxygen to produce 8 moles of carbon dioxide and 9 moles of water
For a complete reaction of 0.760moles of oxygen there are needed:
0.760 mol O₂ ₓ (1 mole C₈H₁₈ / 25/2 moles O₂) = 0.0608 moles of C₈H₁₈
As you have 0.260 moles, the moles of octane that were left are:
0.260 mol - 0.0608 mol = 0.1992 moles of C₈H₁₈
Now, if 0.760 moles of O₂ react, the moles of water that are produced are:
0.760 mol O₂ ₓ (9 moles H₂O / 25/2 moles O₂) = 0.5472 moles of H₂O
