Question

Provide work and answer for 3 and 4

Answer 1

Answer:

Step-by-step explanation:

The geometric mean has a set up it must follow in order to "work". If you look at #3, x is a side of the smaller triangle that has a base of 3, but it's also a side of the large triangle that has a base of 3 + 8 which is 11.  That means that x is your geometric mean. Setting up the geometric mean will look like this:

$\frac{3}{x}=\frac{x}{11}$

where x is the geometric means and the 3 and the 11 (the positions they are in) are the geometric extremes.

Now we cross multiply to solve for x:

$x^2=33$ and

$x=\sqrt{33}$

That's the length of x in #3.

For #4, x is the side of the small triangle with the base of 7 and it's also the side of the large triangle with the base of 7 + 13 which 20. That means that x is the geometric mean. Setting up like above:

$\frac{7}{x}=\frac{x}{20}$ and

$x^2=140$ so

$x=\sqrt{140}$