Answer:
396.92°C
Explanation:
Hello,
This question relates to heat transfer between objects and we can simply use the formula to solve this question.
Data;
Mass of silver (m) = 23g
Initial temperature of silver (T1) = 18°C
Final temperature of silver (T2) = ?
Heat absorbed = 2.05kJ = 2050J
Specific heat capacity of silver = 0.235J/g°C
Heat energy (Q) = mc∇T
Q = MC∇T
Q = heat energy
M = mass of substance
C = specific heat capacity of substance
∇T = change in temperature of substance = (T2 - T1)
Q = MC∇T
2050 = 23 × 0.235 × (T2 - 18)
2050 = 5.41 × (T2 - 18)
2050 = 5.41T2 - 97.38
Collect like terms
2050 + 97.38 = 5.41T2
2147.38 = 5.41T2
Divide both sides by 5.41
2147.38 / 5.41 = 5.41T2 / 5.41
T2 = 396.92°C
The final temperature of the sample after absorbing 2.05kJ of heat is 396.92°C
Have a nice day
