Answer:
Step-by-step explanation:
The histogram shown in the attached file show that the distribution of differences is approximately normal.
So, we can assume that the distribution is normal.
.
b)
The 95% confidence level for [tex]\mu _D=\mu_1-\mu_2[/tex] is found
[tex]\bar d \pm t_{0.025,11}\frac{S_D}{\sqrt{n} }[/tex]
[tex]=0.666667 \pm 2.201\frac{(2.964436)}{\sqrt{12} } \\\\0.666667 \pm 2.201(0.85576)\\\\=0.666667+ 1.883525474=2.5502\\\\=0.666667- 1.883525474=-1.2169\\\\=(-1.2169,2.5502)[/tex]
since 0 is in the confidence interval. we do not reject the null hypothesis.
No, there is no indication of one design language is available.