Answer:
[tex] IQR= Q_3 -Q_1 = 130-100=30[/tex]
We know that below the third quartile we have 75% of the values and below the first quartile we have 25% of the values. Then between the third and the first quartile we will have 75-25%=50% of the values.
And then we can apply the following proportion rule:
[tex] \frac{354}{50} =\frac{x}{100}[/tex]
And solving for x we got:
[tex] x = 100 (\frac{354}{50})=708[/tex]
So then the total of students is approximately 708
Step-by-step explanation:
We know that 354 students are between 100 and 130 so then the interquartile range is:
[tex] IQR= Q_3 -Q_1 = 130-100=30[/tex]
We know that below the third quartile we have 75% of the values and below the first quartile we have 25% of the values. Then between the third and the first quartile we will have 75-25%=50% of the values.
And then we can apply the following proportion rule:
[tex] \frac{354}{50} =\frac{x}{100}[/tex]
And solving for x we got:
[tex] x = 100 (\frac{354}{50})=708[/tex]
So then the total of students is approximately 708