Answer:
THE FINAL TEMPERATURE OF THE LIQUID SAMPLE IS 30.45 DEGREE CELSIUS
Explanation:
Mass of the liquid sample = 1424 g
Initail temperature = 30 degree C
Heat evolved = 1560 J
Specific heat of the liquid = 2.44 J/g degree C
Final temperature = unknown
Since the heat evolved by a substance is the product of the mass, specific heat capacity and the change in temperature of the sample
Heat = Mass * Specific heat * change in temp.
H = m c (T2-T1)
Re-arranging the formula by making T2 (final temperature) the subject of the equation, we have:
T2= H/ m c + T1
So therefore, introducing the value of the variables and solving for T2, we have:
T2 = 1560 / 1424 * 2.44 + 30
T2 = 1560 / 3474.56 + 30
T2 = 0.4487 + 30
T2 = 30.4487 degree C
The final temperature of the liquid sample is approximately 30.45 degree C
