Answer:
[tex]\dfrac{17}{72}[/tex]
Step-by-step explanation:
From the given information:
Total number of students, [tex]n(U)=72[/tex]
The choices were: Chess(C), Swimming(S), and Football(F).
Everyone liked at least one sport except 7 kids, [tex]n( C \cup F \cup S)'=7[/tex]
Chess is not an active sport; and
10 children liked Chess only, [tex]n( C \cap F' \cap S')=10[/tex]
The probability that a randomly-chosen child from this group does not like active kinds of sport is the Probability that a student plays chess only or like no kind of sport at all.
[tex]P( C \cup F \cup S)'+P(C \cap F' \cap S')=\dfrac{n( C \cup F \cup S)'+n(C \cap F' \cap S')}{n(U)} \\=\dfrac{10+7}{72} \\=\dfrac{17}{72}[/tex]