Respuesta :
If the mass of the original sample of Galium-68 is 10 mg, then . . .
== After one half-life, (1/2)(10 mg) = 5 mg remain
== After the second half-life, (1/2)(5 mg) = 2.5 mg remain
== After the third half-life, (1/2)(2.5 mg) = 1.25 mg remain
It doesn't matter how long the half-life is.
The amount of the 10.0mg sample of Galium-68 remaining after;
- One half-life = 5mg
- Two half-life = 2.5mg
- Three half-life = 1.25mg
Irrespective of the half life of an element such as Galium-68; the half-life is the duration of time it takes for the element to remain half it's original mass.
In essence; Since the starting sample of galium-68 has a mass of 10.0mg.
After one half life;
The amount of Galium-68 remaining is; (10/2) mg
- = 5mg
After two half lifes;
The amount of Galium-68 remaining is; (5/2) mg
- = 2.5mg
After three half lifes;
The amount of Galium-68 remaining is; (2.5/2) mg
- = 1.25 mg
Read more;
https://brainly.com/question/23774743