A Broadway theater has 800 ​seats, divided into​ orchestra, main, and balcony seating. Orchestra seats sell for $ 40 comma main seats for $ 30 comma and balcony seats for $ 20.  If all the seats are​ sold, the gross revenue to the theater is $ 23 comma 200.  If all the main and balcony seats are​ sold, but only half the orchestra seats are​ sold, the gross revenue is $ 20 comma 000. How many are there of each kind of​ seat?

orchestra seats: main seats: balcony seats:

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Answer:

orchestra seats: main seats: balcony seats: 160: 400: 240

Step-by-step explanation:

Let number of orchestra seats = x

Let number of main seats = y

Let number of balcony seats = z

As per given statement, total seats are 800

[tex]x +y+z=800 ..... (1)[/tex]

Sales price of each orchestra seat = $40

Sales price of each main seat = $30

Sales price of each balcony seat = $20

If all the seats are sold, total revenue is $23200.

[tex]\Rightarrow 40x + 30y+20z=23200 ...... (2)[/tex]

If all the main and balcony seats are​ sold, but only half the orchestra seats are​ sold, the gross revenue is $ 20 comma 000.

[tex]\Rightarrow 40\times \dfrac{x}{2} + 30y+20z=20000\\\Rightarrow 20x + 30y+20z=20000 ...... (3)[/tex]

Here, we have 3 variables and 3 equations. Let us solve them.

Subtracting Equation (3) from equation (2):

[tex]\Rightarrow 20x = 3200\\\Rightarrow x = 160[/tex]

Putting value of x in equations (1) and (2):

Equation (1)

[tex]\Rightarrow 160 +y+z=800\\\Rightarrow y+z=640 ...... (4)[/tex]

Equation (2)

[tex]\Rightarrow 40\times 160 +30y+20z=23200\\\Rightarrow 30y+20z=16800\\\Rightarrow 3y +2z=1680 ...... (5)[/tex]

Equation (5) - 2 [tex]\times[/tex] Equation(4):

[tex]\Rightarrow y =400[/tex]

Putting value of y in equation (4):

[tex]400 +z = 640\\\Rightarrow z =240[/tex]

Hence, answer is:

orchestra seats: main seats: balcony seats: 160: 400: 240

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