TX is the perpendicular bisector of Su. What is the length of SU?
![TX is the perpendicular bisector of Su What is the length of SU class=](https://us-static.z-dn.net/files/d6a/9da6df74f72d0a0567d2ac9059d1bbea.png)
Answer:
[tex]SU = 20[/tex]
Step-by-step explanation:
Given
Triangle TSU
Bisector TX
Required
Length of SU
A line is said to be a perpendicular bisector if and only if it divides a line segment into two equal lengths;
This means that line TX divides line SU into two equal part.
This implies that
[tex]SU = SX + UX[/tex]
and
[tex]SX = UX[/tex]
Substitute [tex]SX = UX[/tex]; The expression becomes
[tex]SU = UX + UX[/tex]
Recall that [tex]UX = 10[/tex];
So, the above expression becomes
[tex]SU = 10 + 10[/tex]
[tex]SU = 20[/tex]
Hence, the length of is 20