Answer:
15,200in²
Step-by-step explanation:
The tent is shown in the attachment below.
Given=>
Triangular prism tent with the following dimensions:
base (h) = 60in
height of the triangle (h) = 40in
Length of the 3 sides of the triangle respectively (s1, s2, and s3) = 60in, 50in, 50in
Height of the prism (H) = 80in
==>REQUIRED:
Amount of material needed to make the tent = surface area of the triangular prism = bh + (s1 + s2 + s3)*H
==>SOLUTION:
Let us plug in our values using the formula for SA of a triangular prism.
Thus,
SA = 60*40 + (60 + 50 + 50)*80
SA = 2400 + (160)*80
SA = 2400 + 12,800
SA = 15,200in²
Material needed for the tent = 15,200 in²
