Answer:
Either use the formula given below or , Use the formula for volume of a cone .
[tex]h = 36 \\Volume = 588pi\\r = \\588pi = \frac{1}{3}pir^{2} 36\\Cross-multiply\\1764pi=36pir^{2} \\Divide-both-sides-of-the-equation-by-36pi\\r^{2} =\frac{1764pi}{36pi} \\r^{2} = 49\\Square -root-both-sides-of-the-equation.\\\sqrt{r^{2} } =\sqrt{49} \\r = 7[/tex]
Step-by-step explanation:
[tex]Volume -of -a- cone = \frac{1}{3} pir^{2} h\\Method 1 : Make- r- the -subject -of-the-formula.\\V = \frac{1}{3} pir^{2} h \\Cross-multiply\\3V = pir^{2} h \\Divide- both- sides -of- the -equation -by - pih\\\frac{3V}{pih} =r^{2} \\Square-root-both-sides-of-the-equation\\r = \sqrt{\frac{3V}{pih} }[/tex]
