BRAINLIEST FOR WHOEVER GETS THIS RIGHT!!!
PLEASE HELP MATHS QUESTION!!!
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Answer:
Step-by-step explanation:
1) first, lets rationalize the denominator by eliminating [tex]1+\frac{1}{\sqrt{2} }[/tex]
so multiply [tex]\frac{1}{1+\frac{1}{\sqrt{2} } }[/tex] with the conjugate, [tex]1-\frac{1}{\sqrt{2} }[/tex]
we multiply with the conjugate (opposite) since we can take the conjugate and the original term in the form of (a+b)(a-b)= a^2-b^2, which would allow us to get rid of the square root:
so
(1+1/[tex]\sqrt{2}[/tex])(1-[tex]\frac{1}{\sqrt{2} }[/tex])=(1)^2-([tex]\frac{1}{\sqrt{2} }[/tex])^2
hence we are left with:
1-1/2= 0.5
0.5 is the denominator:
since conjugate is multiplied to both numerator and denominator:
for the numerator (1)([tex]1-\frac{1}{\sqrt{2} }[/tex])
is: 1-[tex]\frac{1}{\sqrt{2} }[/tex]
hence, [tex]\frac{1-\frac{1}{\sqrt{2} } }{0.5}[/tex]
so[tex]1-\frac{1}{\sqrt{2} }[/tex]
is 0.292893
so
0.292893/0.5= 0.058579
and 2-sqrt(2)= 0.058579
hence they both are equal
hope this helps!