Question

PLEASE HELP! find f(-2) for f(x) = 2x^x

Answer 1

Answer:

B . $\frac{2}{9}$

Step-by-step explanation:

$3^{-2} =0.1111$

2 x 0.1111 = .2222

$\frac{2}{9} = 0.2222$

Answer 2

Answer:

B. $\frac{2}{9}$

Step-by-step explanation:

We need to find $f(-2)$ for $f(x)=2*3^x$

To do this, we need to replace each instance of x in the equation with -2

$f(x)=2*3^x\\\\f(-2)=2*3^{-2}$

Now, we can remove the negative exponent by rewriting the equation

$f(-2)=2*\frac{1}{3^2}$

And now we can simplify

$f(-2)=2*\frac{1}{9}\\ \\f(-2)=\frac{2}{9}$