Complete Question
The complete question is shown on the first uploaded image
Answer:
The angle P is [tex]P = 26^o[/tex]
Step-by-step explanation:
From the question we are told that
The angle BD is [tex]BD = 154^o[/tex]
Now looking at the diagram we can deduce that angle [tex]B \r CD = 180 ^o[/tex]
Now looking at line AD we see that it is tangent to the circle this implies that line CD is perpendicular to line AD
So we can also deduce that
[tex]B \r C A + D \r C A = 180[/tex]
=> [tex]D \r C A = 180 - 154[/tex]
=> [tex]D \r C A = 26^o[/tex]
Now total angle in a triangle is 180 so
[tex]C\r DA + D\r A C + A \r C D = 180^o[/tex]
Now [tex]D \r A C = 90^o[/tex]
So
[tex]D \r AC = 180 - (90 + 26)[/tex]
=> [tex]P = D \r AC = 26^o[/tex]