Answer:
[tex]y = \frac{3}{2}(x + 8)[/tex]
Explanation:
Given
[tex]y = \frac{3}{2}(x - 8)[/tex]
Required
Equation of line with the same slope and x intercept on negative axis
We start by solving for the slope of the first equation.
It should be noted that the slope of a line (in equation form) is the coefficient of x.
So, we start by opening the bracket of [tex]y = \frac{3}{2}(x - 8)[/tex]
This gives
[tex]y = \frac{3}{2}(x) - \frac{3}{2}(8)[/tex]
[tex]y = \frac{3}{2}(x) - \frac{24}{2}[/tex]
[tex]y = \frac{3}{2}(x) - 12[/tex]
Hence, the slope of the line is [tex]\frac{3}{2}[/tex]
To solve for x intercept, we simply substitute 0 for y. This gives.
[tex]0 = \frac{3}{2}(x) - 12[/tex]
Add 12 to both sides
[tex]12 + 0 = \frac{3}{2}(x) - 12 + 12[/tex]
[tex]12 = \frac{3}{2}(x)[/tex]
Multiply both sides by ⅔
[tex]\frac{2}{3} * 12 = \frac{3}{2}(x) * \frac{2}{3}[/tex]
[tex]\frac{24}{3} = \frac{3}{2}(x) * \frac{2}{3}[/tex]
[tex]\frac{24}{3} = x[/tex]
[tex]8 = x[/tex]
[tex]x = 8[/tex]
This is the x intercept of equation [tex]y = \frac{3}{2}(x - 8)[/tex]
From the question we understand that the second equation has the same slope and has a negative x intercept as [tex]y = \frac{3}{2}(x - 8)[/tex]
For two parallel lines, their slope are always equal.
Hence, the second equation has the following info.
[tex]Slope = \frac{3}{2}[/tex]
[tex]x,intercept = -8[/tex]
This can be rewritten as follows;.
x = -8
Add 8 to both sides
x + 8 = -8 + 8
x + 8 = 0
Multiply both sides by the slope (3/2)
[tex]\frac{3}{2}(x + 8) = \frac{3}{2} * 0[/tex]
[tex]\frac{3}{2}(x + 8) = 0[/tex]
Recall that to solve for x intercept, we simply substitute 0 for y.
At this point, we also replace 0 with y.
This gives
[tex]\frac{3}{2}(x + 8) = y[/tex]
[tex]y = \frac{3}{2}(x + 8)[/tex]
Hence, the equation of the second line is [tex]y = \frac{3}{2}(x + 8)[/tex]