Armco, a manufacturer of traffic light systems, found 95% of the newly developed systems lasted 3 years before failing to change signals properly. If a city purchased four of these systems, what is the probability all four systems would operate properly for at least 3 years

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Answer:

81.45% probability all four systems would operate properly for at least 3 years

Step-by-step explanation:

For each traffic light, there are only two possible outcomes. Either they work for at least 3 years, or they do not. The probability of a light working at least 3 years is independent of other lights. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

95% of the newly developed systems lasted 3 years

This means that [tex]p = 0.95[/tex]

The city purchases four systems

This means that [tex]n = 4[/tex]

What is the probability all four systems would operate properly for at least 3 years

This is P(X = 4).

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{4,4}.(0.95)^{4}.(0.05)^{0} = 0.8145[/tex]

81.45% probability all four systems would operate properly for at least 3 years

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