Question

Find the probability that a randomly selected car from this sample had 222 doors or 444 doors. P\left(\text{2 doors OR 4 doors}\right)=P(2 doors OR 4 doors)=P, (, start text, 2, space, d, o, o, r, s, space, O, R, space, 4, space, d, o, o, r, s, end text, ), equals

Answer 1

Answer:

77/100 or 0.77

Step-by-step explanation:

The question lacks appropriate diagram. Find the diagram attached below.

Probability is the likelihood or chance that an event will occur.

Probability  = expected outcome of event/total outcome of event

According to the set diagram;

the total number of cars that has 2 doors = 14+18 = 32

the total number of cars that has 4 doors = 20+25 = 45

Probability of randomly selecting a car that has 2 doors = 32/100

Probability of randomly selecting a car that has 4 doors = 45/100

Probability that a randomly selected car from this sample had 2 doors or 4 doors = P(2 or 4) = 32/100+45/100

= 77/100

Answer 2

Answer:

Yes, they are mutually exclusive.

Step-by-step explanation:

Here is Khan Academy's explanation:

Are the events mutually exclusive?

Mutually exclusive events cannot happen at the same time.

There are no cars in this sample that had both the two doors feature and four doors feature.

So these events are mutually exclusive.