Answer:
6w = 30
Step-by-step explanation:
We should know that the 30 inches of framing material were used to frame the four sides of the rectangle.
The perimeter of the rectangle is what we should be considering, whenever we are dealing with frames.
This is 2 X (length + width)
From the questions, we can get the dimensions of the rectangle using clues from the various statements made.
From the statement"a rectangular painting length more than twice the width" we can see that the
L = 2w ------------------------- equation 1
substituting this value into the formula for the perimeter of the rectangle we have
30 = 2(2w + w)
30 = 6w
w= 5
from equation 1
L =2 X (5) = 10
Hence, we can set up the equation
6w = 30
However, the closest option to what we have is option D
6w + 6 = 30 - 4
complete question:
Lisa is framing a rectangular painting. The length is three more than twice the width. She uses 30 inches of framing material. What is the length of the printing? Write an equation and solve
Answer:
D.6w + 6 = 30 = 4
Step-by-step explanation:
perimeter = 30 inches
width = w
length = 2w + 3
perimeter of a rectangle = 2l + 2w
where
w = width
l = length
Therefore,
perimeter of a rectangle = 2(2w + 3) + 2w
perimeter of the rectangle = 4w + 6 + 2w
perimeter = 6w + 6
recall
perimeter = 30 inches
6w + 6 = 30
6w = 24
divide both sides by 6
w = 24/6
w = 4
