Answer:
the g's contributing term for the overall uncertainty of P is [tex]dP_g = [\frac{dg}{g}][/tex]
Step-by-step explanation:
From the question we are told that
The pressure is [tex]P = P_o + \rho gh[/tex]
The first step in determining the uncertainty of P in by obtaining the terms in the equation contributing to it uncertainty and to do that we take the Ln of both sides of the equation
[tex]ln P = lnP_o + ln(\rho gh )[/tex]
=> [tex]ln P = lnP_o + ln \rho + ln g + ln h[/tex]
Then the next step is to differentiate both sides of the equation
[tex]\frac{d(ln P)}{dP} = \frac{d(ln P_o)}{dP_o} + \frac{d(ln \rho)}{d\rho} +\frac{d(ln g)}{dg} + \frac{d(ln h)}{dh}[/tex]
=> [tex]\frac{dP}{P} = \frac{dP_o}{P_o} + \frac{d \rho}{\rho} +\frac{d g}{g} + \frac{d h}{h}[/tex]
We asked to obtain the contribution of the term g to the uncertainty of P
This can deduced from the above equation as
[tex]dP_g = [\frac{dg}{g}] P[/tex]