Respuesta :
Explanation:
The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.
H2SO4
1 mol of H2SO4 contains 4 mol of O
x mol of H2SO4 would contain 3.10 mol of O
x = 3.10 * 1 / 4 = 0.775 mol of H2SO4
C2H4O2
1 mol of C2H4O2 contains 2 mol of O
x mol of C2H4O2 would contain 3.10 mol of O
x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2
NaOH
1 mol of NaOH contains 1 mol of O
x mol of NaOH would contain 3.10 mol of O
x = 3.10 * 1 / 1 = 3.10 mol of NaOH
1. The moles of [tex]H_2SO_4[/tex] is 0.775 mol.
2. The moles of [tex]C_2H_4O_2[/tex] is 1.55 mol.
3. The moles of [tex]NaOH[/tex] is 3.10 mol.
Given:
Moles of O =3.10
Number of moles:
- It is defined as given mass over molar mass.
- [tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
1. Calculation for moles of [tex]H_2SO_4[/tex]:
1 mol of [tex]H_2SO_4[/tex] contains 4 mol of O
x mol of [tex]H_2SO_4[/tex] would contain 3.10 mol of O
x = 3.10 * 1 / 4 = 0.775 mol of [tex]H_2SO_4[/tex]
2. Calculation for moles of [tex]C_2H_4O_2[/tex] :
1 mol of [tex]C_2H_4O_2[/tex] contains 2 mol of O
x mol of [tex]C_2H_4O_2[/tex] would contain 3.10 mol of O
x = 3.10 * 1 / 2 = 1.55 mol of [tex]C_2H_4O_2[/tex]
3.Calculation of moles of [tex]NaOH[/tex] :
1 mol of [tex]NaOH[/tex] contains 1 mol of O
x mol of [tex]NaOH[/tex]would contain 3.10 mol of O
x = 3.10 * 1 / 1 = 3.10 mol of [tex]NaOH[/tex]
Find more information about Number of moles here:
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