pls help i need answer
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Answer:
14m
Step-by-step explanation:
Step1:
Consider the first right angled triangle using Pythagoras Theorem:
(hyponenus)^2 = (opposite)^2 + (adjacent)^2
20^2 = 12^2 + A^2
A^2 = 400 - 144 = 256
A = Square root of 256 = 16m
Step2:
CONSIDER THE SECOND RIGHT_ ANGLED TRIANGLE:
adjacent=24-16=8m
opposite=12m
Hypotenus=?
(hypotenus)^2 = (opposite)^2 + (adjacent)^2
H^2=12^2+8^2=
144+64
H^2=208
H=square root of 208=14.42m
To the nearest meter=14m
Hope it helps.
Answer:
b. 14 m
Step-by-step explanation:
base of left side triangle
base of right side triangle
missing length
Option b. 14 m is closest one